3.117 \(\int \frac {(c+d x)^2}{(a+a \cosh (e+f x))^2} \, dx\)

Optimal. Leaf size=200 \[ -\frac {4 d (c+d x) \log \left (e^{e+f x}+1\right )}{3 a^2 f^2}+\frac {d (c+d x) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^2}+\frac {(c+d x)^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f}+\frac {(c+d x)^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right ) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{6 a^2 f}+\frac {(c+d x)^2}{3 a^2 f}-\frac {4 d^2 \text {Li}_2\left (-e^{e+f x}\right )}{3 a^2 f^3}-\frac {2 d^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^3} \]

[Out]

1/3*(d*x+c)^2/a^2/f-4/3*d*(d*x+c)*ln(1+exp(f*x+e))/a^2/f^2-4/3*d^2*polylog(2,-exp(f*x+e))/a^2/f^3+1/3*d*(d*x+c
)*sech(1/2*e+1/2*f*x)^2/a^2/f^2-2/3*d^2*tanh(1/2*e+1/2*f*x)/a^2/f^3+1/3*(d*x+c)^2*tanh(1/2*e+1/2*f*x)/a^2/f+1/
6*(d*x+c)^2*sech(1/2*e+1/2*f*x)^2*tanh(1/2*e+1/2*f*x)/a^2/f

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Rubi [A]  time = 0.25, antiderivative size = 200, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 9, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.450, Rules used = {3318, 4186, 3767, 8, 4184, 3718, 2190, 2279, 2391} \[ -\frac {4 d^2 \text {PolyLog}\left (2,-e^{e+f x}\right )}{3 a^2 f^3}-\frac {4 d (c+d x) \log \left (e^{e+f x}+1\right )}{3 a^2 f^2}+\frac {d (c+d x) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^2}+\frac {(c+d x)^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f}+\frac {(c+d x)^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right ) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{6 a^2 f}+\frac {(c+d x)^2}{3 a^2 f}-\frac {2 d^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^3} \]

Antiderivative was successfully verified.

[In]

Int[(c + d*x)^2/(a + a*Cosh[e + f*x])^2,x]

[Out]

(c + d*x)^2/(3*a^2*f) - (4*d*(c + d*x)*Log[1 + E^(e + f*x)])/(3*a^2*f^2) - (4*d^2*PolyLog[2, -E^(e + f*x)])/(3
*a^2*f^3) + (d*(c + d*x)*Sech[e/2 + (f*x)/2]^2)/(3*a^2*f^2) - (2*d^2*Tanh[e/2 + (f*x)/2])/(3*a^2*f^3) + ((c +
d*x)^2*Tanh[e/2 + (f*x)/2])/(3*a^2*f) + ((c + d*x)^2*Sech[e/2 + (f*x)/2]^2*Tanh[e/2 + (f*x)/2])/(6*a^2*f)

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 2190

Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/((a_) + (b_.)*((F_)^((g_.)*((e_.) +
 (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[((c + d*x)^m*Log[1 + (b*(F^(g*(e + f*x)))^n)/a])/(b*f*g*n*Log[F]), x]
 - Dist[(d*m)/(b*f*g*n*Log[F]), Int[(c + d*x)^(m - 1)*Log[1 + (b*(F^(g*(e + f*x)))^n)/a], x], x] /; FreeQ[{F,
a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]

Rule 2279

Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Dist[1/(d*e*n*Log[F]), Subst[Int
[Log[a + b*x]/x, x], x, (F^(e*(c + d*x)))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
 e, n}, x] && EqQ[c*d, 1]

Rule 3318

Int[((c_.) + (d_.)*(x_))^(m_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Dist[(2*a)^n, Int[(c
 + d*x)^m*Sin[(1*(e + (Pi*a)/(2*b)))/2 + (f*x)/2]^(2*n), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[a^2
- b^2, 0] && IntegerQ[n] && (GtQ[n, 0] || IGtQ[m, 0])

Rule 3718

Int[((c_.) + (d_.)*(x_))^(m_.)*tan[(e_.) + (Complex[0, fz_])*(f_.)*(x_)], x_Symbol] :> -Simp[(I*(c + d*x)^(m +
 1))/(d*(m + 1)), x] + Dist[2*I, Int[((c + d*x)^m*E^(2*(-(I*e) + f*fz*x)))/(1 + E^(2*(-(I*e) + f*fz*x))), x],
x] /; FreeQ[{c, d, e, f, fz}, x] && IGtQ[m, 0]

Rule 3767

Int[csc[(c_.) + (d_.)*(x_)]^(n_), x_Symbol] :> -Dist[d^(-1), Subst[Int[ExpandIntegrand[(1 + x^2)^(n/2 - 1), x]
, x], x, Cot[c + d*x]], x] /; FreeQ[{c, d}, x] && IGtQ[n/2, 0]

Rule 4184

Int[csc[(e_.) + (f_.)*(x_)]^2*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> -Simp[((c + d*x)^m*Cot[e + f*x])/f, x]
+ Dist[(d*m)/f, Int[(c + d*x)^(m - 1)*Cot[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && GtQ[m, 0]

Rule 4186

Int[(csc[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> -Simp[(b^2*(c + d*x)^m*Cot[e
+ f*x]*(b*Csc[e + f*x])^(n - 2))/(f*(n - 1)), x] + (Dist[(b^2*d^2*m*(m - 1))/(f^2*(n - 1)*(n - 2)), Int[(c + d
*x)^(m - 2)*(b*Csc[e + f*x])^(n - 2), x], x] + Dist[(b^2*(n - 2))/(n - 1), Int[(c + d*x)^m*(b*Csc[e + f*x])^(n
 - 2), x], x] - Simp[(b^2*d*m*(c + d*x)^(m - 1)*(b*Csc[e + f*x])^(n - 2))/(f^2*(n - 1)*(n - 2)), x]) /; FreeQ[
{b, c, d, e, f}, x] && GtQ[n, 1] && NeQ[n, 2] && GtQ[m, 1]

Rubi steps

\begin {align*} \int \frac {(c+d x)^2}{(a+a \cosh (e+f x))^2} \, dx &=\frac {\int (c+d x)^2 \csc ^4\left (\frac {1}{2} (i e+\pi )+\frac {i f x}{2}\right ) \, dx}{4 a^2}\\ &=\frac {d (c+d x) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^2}+\frac {(c+d x)^2 \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right ) \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{6 a^2 f}+\frac {\int (c+d x)^2 \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right ) \, dx}{6 a^2}-\frac {d^2 \int \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right ) \, dx}{3 a^2 f^2}\\ &=\frac {d (c+d x) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^2}+\frac {(c+d x)^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f}+\frac {(c+d x)^2 \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right ) \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{6 a^2 f}-\frac {\left (2 i d^2\right ) \operatorname {Subst}\left (\int 1 \, dx,x,-i \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )\right )}{3 a^2 f^3}-\frac {(2 d) \int (c+d x) \tanh \left (\frac {e}{2}+\frac {f x}{2}\right ) \, dx}{3 a^2 f}\\ &=\frac {(c+d x)^2}{3 a^2 f}+\frac {d (c+d x) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^2}-\frac {2 d^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^3}+\frac {(c+d x)^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f}+\frac {(c+d x)^2 \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right ) \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{6 a^2 f}-\frac {(4 d) \int \frac {e^{2 \left (\frac {e}{2}+\frac {f x}{2}\right )} (c+d x)}{1+e^{2 \left (\frac {e}{2}+\frac {f x}{2}\right )}} \, dx}{3 a^2 f}\\ &=\frac {(c+d x)^2}{3 a^2 f}-\frac {4 d (c+d x) \log \left (1+e^{e+f x}\right )}{3 a^2 f^2}+\frac {d (c+d x) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^2}-\frac {2 d^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^3}+\frac {(c+d x)^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f}+\frac {(c+d x)^2 \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right ) \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{6 a^2 f}+\frac {\left (4 d^2\right ) \int \log \left (1+e^{2 \left (\frac {e}{2}+\frac {f x}{2}\right )}\right ) \, dx}{3 a^2 f^2}\\ &=\frac {(c+d x)^2}{3 a^2 f}-\frac {4 d (c+d x) \log \left (1+e^{e+f x}\right )}{3 a^2 f^2}+\frac {d (c+d x) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^2}-\frac {2 d^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^3}+\frac {(c+d x)^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f}+\frac {(c+d x)^2 \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right ) \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{6 a^2 f}+\frac {\left (4 d^2\right ) \operatorname {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 \left (\frac {e}{2}+\frac {f x}{2}\right )}\right )}{3 a^2 f^3}\\ &=\frac {(c+d x)^2}{3 a^2 f}-\frac {4 d (c+d x) \log \left (1+e^{e+f x}\right )}{3 a^2 f^2}-\frac {4 d^2 \text {Li}_2\left (-e^{e+f x}\right )}{3 a^2 f^3}+\frac {d (c+d x) \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^2}-\frac {2 d^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f^3}+\frac {(c+d x)^2 \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{3 a^2 f}+\frac {(c+d x)^2 \text {sech}^2\left (\frac {e}{2}+\frac {f x}{2}\right ) \tanh \left (\frac {e}{2}+\frac {f x}{2}\right )}{6 a^2 f}\\ \end {align*}

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Mathematica [C]  time = 6.48, size = 637, normalized size = 3.18 \[ \frac {\text {sech}\left (\frac {e}{2}\right ) \cosh \left (\frac {e}{2}+\frac {f x}{2}\right ) \left (c^2 f^2 \sinh \left (e+\frac {3 f x}{2}\right )+3 c^2 f^2 \sinh \left (\frac {f x}{2}\right )+2 c d f^2 x \sinh \left (e+\frac {3 f x}{2}\right )+2 c d f \cosh \left (e+\frac {f x}{2}\right )+6 c d f^2 x \sinh \left (\frac {f x}{2}\right )+2 c d f \cosh \left (\frac {f x}{2}\right )+d^2 f^2 x^2 \sinh \left (e+\frac {3 f x}{2}\right )+2 d^2 \sinh \left (e+\frac {f x}{2}\right )-2 d^2 \sinh \left (e+\frac {3 f x}{2}\right )+2 d^2 f x \cosh \left (e+\frac {f x}{2}\right )+3 d^2 f^2 x^2 \sinh \left (\frac {f x}{2}\right )-4 d^2 \sinh \left (\frac {f x}{2}\right )+2 d^2 f x \cosh \left (\frac {f x}{2}\right )\right )}{3 f^3 (a \cosh (e+f x)+a)^2}-\frac {16 c d \text {sech}\left (\frac {e}{2}\right ) \cosh ^4\left (\frac {e}{2}+\frac {f x}{2}\right ) \left (\cosh \left (\frac {e}{2}\right ) \log \left (\sinh \left (\frac {e}{2}\right ) \sinh \left (\frac {f x}{2}\right )+\cosh \left (\frac {e}{2}\right ) \cosh \left (\frac {f x}{2}\right )\right )-\frac {1}{2} f x \sinh \left (\frac {e}{2}\right )\right )}{3 f^2 \left (\cosh ^2\left (\frac {e}{2}\right )-\sinh ^2\left (\frac {e}{2}\right )\right ) (a \cosh (e+f x)+a)^2}-\frac {16 d^2 \text {csch}\left (\frac {e}{2}\right ) \text {sech}\left (\frac {e}{2}\right ) \cosh ^4\left (\frac {e}{2}+\frac {f x}{2}\right ) \left (\frac {1}{4} f^2 x^2 e^{-\tanh ^{-1}\left (\coth \left (\frac {e}{2}\right )\right )}-\frac {i \coth \left (\frac {e}{2}\right ) \left (i \text {Li}_2\left (e^{2 i \left (\frac {i f x}{2}+i \tanh ^{-1}\left (\coth \left (\frac {e}{2}\right )\right )\right )}\right )-\frac {1}{2} f x \left (-\pi +2 i \tanh ^{-1}\left (\coth \left (\frac {e}{2}\right )\right )\right )-2 \left (i \tanh ^{-1}\left (\coth \left (\frac {e}{2}\right )\right )+\frac {i f x}{2}\right ) \log \left (1-e^{2 i \left (i \tanh ^{-1}\left (\coth \left (\frac {e}{2}\right )\right )+\frac {i f x}{2}\right )}\right )+2 i \tanh ^{-1}\left (\coth \left (\frac {e}{2}\right )\right ) \log \left (i \sinh \left (\tanh ^{-1}\left (\coth \left (\frac {e}{2}\right )\right )+\frac {f x}{2}\right )\right )-\pi \log \left (e^{f x}+1\right )+\pi \log \left (\cosh \left (\frac {f x}{2}\right )\right )\right )}{\sqrt {1-\coth ^2\left (\frac {e}{2}\right )}}\right )}{3 f^3 \sqrt {\text {csch}^2\left (\frac {e}{2}\right ) \left (\sinh ^2\left (\frac {e}{2}\right )-\cosh ^2\left (\frac {e}{2}\right )\right )} (a \cosh (e+f x)+a)^2} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(c + d*x)^2/(a + a*Cosh[e + f*x])^2,x]

[Out]

(-16*c*d*Cosh[e/2 + (f*x)/2]^4*Sech[e/2]*(Cosh[e/2]*Log[Cosh[e/2]*Cosh[(f*x)/2] + Sinh[e/2]*Sinh[(f*x)/2]] - (
f*x*Sinh[e/2])/2))/(3*f^2*(a + a*Cosh[e + f*x])^2*(Cosh[e/2]^2 - Sinh[e/2]^2)) - (16*d^2*Cosh[e/2 + (f*x)/2]^4
*Csch[e/2]*((f^2*x^2)/(4*E^ArcTanh[Coth[e/2]]) - (I*Coth[e/2]*(-1/2*(f*x*(-Pi + (2*I)*ArcTanh[Coth[e/2]])) - P
i*Log[1 + E^(f*x)] - 2*((I/2)*f*x + I*ArcTanh[Coth[e/2]])*Log[1 - E^((2*I)*((I/2)*f*x + I*ArcTanh[Coth[e/2]]))
] + Pi*Log[Cosh[(f*x)/2]] + (2*I)*ArcTanh[Coth[e/2]]*Log[I*Sinh[(f*x)/2 + ArcTanh[Coth[e/2]]]] + I*PolyLog[2,
E^((2*I)*((I/2)*f*x + I*ArcTanh[Coth[e/2]]))]))/Sqrt[1 - Coth[e/2]^2])*Sech[e/2])/(3*f^3*(a + a*Cosh[e + f*x])
^2*Sqrt[Csch[e/2]^2*(-Cosh[e/2]^2 + Sinh[e/2]^2)]) + (Cosh[e/2 + (f*x)/2]*Sech[e/2]*(2*c*d*f*Cosh[(f*x)/2] + 2
*d^2*f*x*Cosh[(f*x)/2] + 2*c*d*f*Cosh[e + (f*x)/2] + 2*d^2*f*x*Cosh[e + (f*x)/2] - 4*d^2*Sinh[(f*x)/2] + 3*c^2
*f^2*Sinh[(f*x)/2] + 6*c*d*f^2*x*Sinh[(f*x)/2] + 3*d^2*f^2*x^2*Sinh[(f*x)/2] + 2*d^2*Sinh[e + (f*x)/2] - 2*d^2
*Sinh[e + (3*f*x)/2] + c^2*f^2*Sinh[e + (3*f*x)/2] + 2*c*d*f^2*x*Sinh[e + (3*f*x)/2] + d^2*f^2*x^2*Sinh[e + (3
*f*x)/2]))/(3*f^3*(a + a*Cosh[e + f*x])^2)

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fricas [B]  time = 0.69, size = 963, normalized size = 4.82 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)^2/(a+a*cosh(f*x+e))^2,x, algorithm="fricas")

[Out]

-2/3*(d^2*e^2 - 2*c*d*e*f + c^2*f^2 - (d^2*f^2*x^2 + 2*c*d*f^2*x - d^2*e^2 + 2*c*d*e*f)*cosh(f*x + e)^3 - (d^2
*f^2*x^2 + 2*c*d*f^2*x - d^2*e^2 + 2*c*d*e*f)*sinh(f*x + e)^3 - (3*d^2*f^2*x^2 - 3*d^2*e^2 + 2*d^2 + 2*(3*c*d*
e + c*d)*f + 2*(3*c*d*f^2 + d^2*f)*x)*cosh(f*x + e)^2 - (3*d^2*f^2*x^2 - 3*d^2*e^2 + 2*d^2 + 2*(3*c*d*e + c*d)
*f + 2*(3*c*d*f^2 + d^2*f)*x + 3*(d^2*f^2*x^2 + 2*c*d*f^2*x - d^2*e^2 + 2*c*d*e*f)*cosh(f*x + e))*sinh(f*x + e
)^2 - 2*d^2 + (3*d^2*e^2 + 3*c^2*f^2 - 2*d^2*f*x - 4*d^2 - 2*(3*c*d*e + c*d)*f)*cosh(f*x + e) + 2*(d^2*cosh(f*
x + e)^3 + d^2*sinh(f*x + e)^3 + 3*d^2*cosh(f*x + e)^2 + 3*d^2*cosh(f*x + e) + 3*(d^2*cosh(f*x + e) + d^2)*sin
h(f*x + e)^2 + d^2 + 3*(d^2*cosh(f*x + e)^2 + 2*d^2*cosh(f*x + e) + d^2)*sinh(f*x + e))*dilog(-cosh(f*x + e) -
 sinh(f*x + e)) + 2*(d^2*f*x + (d^2*f*x + c*d*f)*cosh(f*x + e)^3 + (d^2*f*x + c*d*f)*sinh(f*x + e)^3 + c*d*f +
 3*(d^2*f*x + c*d*f)*cosh(f*x + e)^2 + 3*(d^2*f*x + c*d*f + (d^2*f*x + c*d*f)*cosh(f*x + e))*sinh(f*x + e)^2 +
 3*(d^2*f*x + c*d*f)*cosh(f*x + e) + 3*(d^2*f*x + c*d*f + (d^2*f*x + c*d*f)*cosh(f*x + e)^2 + 2*(d^2*f*x + c*d
*f)*cosh(f*x + e))*sinh(f*x + e))*log(cosh(f*x + e) + sinh(f*x + e) + 1) + (3*d^2*e^2 + 3*c^2*f^2 - 2*d^2*f*x
- 3*(d^2*f^2*x^2 + 2*c*d*f^2*x - d^2*e^2 + 2*c*d*e*f)*cosh(f*x + e)^2 - 4*d^2 - 2*(3*c*d*e + c*d)*f - 2*(3*d^2
*f^2*x^2 - 3*d^2*e^2 + 2*d^2 + 2*(3*c*d*e + c*d)*f + 2*(3*c*d*f^2 + d^2*f)*x)*cosh(f*x + e))*sinh(f*x + e))/(a
^2*f^3*cosh(f*x + e)^3 + a^2*f^3*sinh(f*x + e)^3 + 3*a^2*f^3*cosh(f*x + e)^2 + 3*a^2*f^3*cosh(f*x + e) + a^2*f
^3 + 3*(a^2*f^3*cosh(f*x + e) + a^2*f^3)*sinh(f*x + e)^2 + 3*(a^2*f^3*cosh(f*x + e)^2 + 2*a^2*f^3*cosh(f*x + e
) + a^2*f^3)*sinh(f*x + e))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (d x + c\right )}^{2}}{{\left (a \cosh \left (f x + e\right ) + a\right )}^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)^2/(a+a*cosh(f*x+e))^2,x, algorithm="giac")

[Out]

integrate((d*x + c)^2/(a*cosh(f*x + e) + a)^2, x)

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maple [A]  time = 0.24, size = 313, normalized size = 1.56 \[ -\frac {2 \left (3 f^{2} d^{2} x^{2} {\mathrm e}^{f x +e}+6 f^{2} c d x \,{\mathrm e}^{f x +e}+d^{2} f^{2} x^{2}-2 d^{2} f x \,{\mathrm e}^{2 f x +2 e}+3 f^{2} c^{2} {\mathrm e}^{f x +e}+2 c d \,f^{2} x -2 c d f \,{\mathrm e}^{2 f x +2 e}-2 f \,d^{2} x \,{\mathrm e}^{f x +e}+c^{2} f^{2}-2 f c d \,{\mathrm e}^{f x +e}-2 d^{2} {\mathrm e}^{2 f x +2 e}-4 d^{2} {\mathrm e}^{f x +e}-2 d^{2}\right )}{3 f^{3} a^{2} \left ({\mathrm e}^{f x +e}+1\right )^{3}}-\frac {4 d c \ln \left ({\mathrm e}^{f x +e}+1\right )}{3 a^{2} f^{2}}+\frac {4 d c \ln \left ({\mathrm e}^{f x +e}\right )}{3 a^{2} f^{2}}+\frac {2 d^{2} x^{2}}{3 a^{2} f}+\frac {4 d^{2} e x}{3 a^{2} f^{2}}+\frac {2 d^{2} e^{2}}{3 a^{2} f^{3}}-\frac {4 d^{2} \ln \left ({\mathrm e}^{f x +e}+1\right ) x}{3 a^{2} f^{2}}-\frac {4 d^{2} \polylog \left (2, -{\mathrm e}^{f x +e}\right )}{3 a^{2} f^{3}}-\frac {4 d^{2} e \ln \left ({\mathrm e}^{f x +e}\right )}{3 a^{2} f^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*x+c)^2/(a+a*cosh(f*x+e))^2,x)

[Out]

-2/3*(3*f^2*d^2*x^2*exp(f*x+e)+6*f^2*c*d*x*exp(f*x+e)+d^2*f^2*x^2-2*d^2*f*x*exp(2*f*x+2*e)+3*f^2*c^2*exp(f*x+e
)+2*c*d*f^2*x-2*c*d*f*exp(2*f*x+2*e)-2*f*d^2*x*exp(f*x+e)+c^2*f^2-2*f*c*d*exp(f*x+e)-2*d^2*exp(2*f*x+2*e)-4*d^
2*exp(f*x+e)-2*d^2)/f^3/a^2/(exp(f*x+e)+1)^3-4/3/a^2*d/f^2*c*ln(exp(f*x+e)+1)+4/3/a^2*d/f^2*c*ln(exp(f*x+e))+2
/3/a^2*d^2/f*x^2+4/3/a^2*d^2/f^2*e*x+2/3/a^2*d^2/f^3*e^2-4/3/a^2*d^2/f^2*ln(exp(f*x+e)+1)*x-4/3*d^2*polylog(2,
-exp(f*x+e))/a^2/f^3-4/3/a^2*d^2/f^3*e*ln(exp(f*x+e))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {2}{3} \, d^{2} {\left (\frac {f^{2} x^{2} - 2 \, {\left (f x e^{\left (2 \, e\right )} + e^{\left (2 \, e\right )}\right )} e^{\left (2 \, f x\right )} + {\left (3 \, f^{2} x^{2} e^{e} - 2 \, f x e^{e} - 4 \, e^{e}\right )} e^{\left (f x\right )} - 2}{a^{2} f^{3} e^{\left (3 \, f x + 3 \, e\right )} + 3 \, a^{2} f^{3} e^{\left (2 \, f x + 2 \, e\right )} + 3 \, a^{2} f^{3} e^{\left (f x + e\right )} + a^{2} f^{3}} - 6 \, \int \frac {x}{3 \, {\left (a^{2} f e^{\left (f x + e\right )} + a^{2} f\right )}}\,{d x}\right )} + \frac {4}{3} \, c d {\left (\frac {f x e^{\left (3 \, f x + 3 \, e\right )} + {\left (3 \, f x e^{\left (2 \, e\right )} + e^{\left (2 \, e\right )}\right )} e^{\left (2 \, f x\right )} + e^{\left (f x + e\right )}}{a^{2} f^{2} e^{\left (3 \, f x + 3 \, e\right )} + 3 \, a^{2} f^{2} e^{\left (2 \, f x + 2 \, e\right )} + 3 \, a^{2} f^{2} e^{\left (f x + e\right )} + a^{2} f^{2}} - \frac {\log \left ({\left (e^{\left (f x + e\right )} + 1\right )} e^{\left (-e\right )}\right )}{a^{2} f^{2}}\right )} + \frac {2}{3} \, c^{2} {\left (\frac {3 \, e^{\left (-f x - e\right )}}{{\left (3 \, a^{2} e^{\left (-f x - e\right )} + 3 \, a^{2} e^{\left (-2 \, f x - 2 \, e\right )} + a^{2} e^{\left (-3 \, f x - 3 \, e\right )} + a^{2}\right )} f} + \frac {1}{{\left (3 \, a^{2} e^{\left (-f x - e\right )} + 3 \, a^{2} e^{\left (-2 \, f x - 2 \, e\right )} + a^{2} e^{\left (-3 \, f x - 3 \, e\right )} + a^{2}\right )} f}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)^2/(a+a*cosh(f*x+e))^2,x, algorithm="maxima")

[Out]

-2/3*d^2*((f^2*x^2 - 2*(f*x*e^(2*e) + e^(2*e))*e^(2*f*x) + (3*f^2*x^2*e^e - 2*f*x*e^e - 4*e^e)*e^(f*x) - 2)/(a
^2*f^3*e^(3*f*x + 3*e) + 3*a^2*f^3*e^(2*f*x + 2*e) + 3*a^2*f^3*e^(f*x + e) + a^2*f^3) - 6*integrate(1/3*x/(a^2
*f*e^(f*x + e) + a^2*f), x)) + 4/3*c*d*((f*x*e^(3*f*x + 3*e) + (3*f*x*e^(2*e) + e^(2*e))*e^(2*f*x) + e^(f*x +
e))/(a^2*f^2*e^(3*f*x + 3*e) + 3*a^2*f^2*e^(2*f*x + 2*e) + 3*a^2*f^2*e^(f*x + e) + a^2*f^2) - log((e^(f*x + e)
 + 1)*e^(-e))/(a^2*f^2)) + 2/3*c^2*(3*e^(-f*x - e)/((3*a^2*e^(-f*x - e) + 3*a^2*e^(-2*f*x - 2*e) + a^2*e^(-3*f
*x - 3*e) + a^2)*f) + 1/((3*a^2*e^(-f*x - e) + 3*a^2*e^(-2*f*x - 2*e) + a^2*e^(-3*f*x - 3*e) + a^2)*f))

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (c+d\,x\right )}^2}{{\left (a+a\,\mathrm {cosh}\left (e+f\,x\right )\right )}^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c + d*x)^2/(a + a*cosh(e + f*x))^2,x)

[Out]

int((c + d*x)^2/(a + a*cosh(e + f*x))^2, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {c^{2}}{\cosh ^{2}{\left (e + f x \right )} + 2 \cosh {\left (e + f x \right )} + 1}\, dx + \int \frac {d^{2} x^{2}}{\cosh ^{2}{\left (e + f x \right )} + 2 \cosh {\left (e + f x \right )} + 1}\, dx + \int \frac {2 c d x}{\cosh ^{2}{\left (e + f x \right )} + 2 \cosh {\left (e + f x \right )} + 1}\, dx}{a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)**2/(a+a*cosh(f*x+e))**2,x)

[Out]

(Integral(c**2/(cosh(e + f*x)**2 + 2*cosh(e + f*x) + 1), x) + Integral(d**2*x**2/(cosh(e + f*x)**2 + 2*cosh(e
+ f*x) + 1), x) + Integral(2*c*d*x/(cosh(e + f*x)**2 + 2*cosh(e + f*x) + 1), x))/a**2

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